Do you like Mathematics?

I can remember working out sums like this under the subjec "Permutations and Combinations" about 30 years ago in school. I'll try my best, but I am eagerly waiting for the correct solution. This is an 8 letter word. It has 3 Es. But there is a limitation regarding E. So we will forget it and think of this as a 5 letter word. The number of words you can make with 5 letters is, 5x4x3x2x1. This works out to 120. But the D repeating two times brings this down by half. So the numebr of words are 60. Now lets take one 5 letter words. It has 6 spots to insert another letter without touching each other. So in how many ways can we put 3 Es into these 6 spots. I think it is 6x5x4/3x2. That is 20. So altogether there are (60 x 20) 1200 possibilities.