problems in physics...how to do it?

Philippines
November 29, 2007 5:17pm CST
1.) A girl weighing 620 N sits in the middle of a 2.8-meter long hammock which sags 1.2 m below the point of support. What force is exerted by each of the sags of the two ropes supporting the hammock? 2.) A uniform bar is 4 m long. It weighs 300 N. At one end, 1 m from the pivot point, there is a resisting weight of 2000 N. What force must be applied at the other end to produce equilibrium? thanks a lot!
4 responses
@marsher (32)
• China
30 Nov 07
ha it seems that the answers are 1)F/1.4=630/2*1.2 2)according to the theory of lever you can get the equation of balance 3*F+3*300*1.5/4=0.5*300/4+1*2000 F=1700/3 N
1 person likes this
• Philippines
30 Nov 07
i don't quite understand your number 1...umm how did you do it...?? number 2 is also confusing :p
@stvasile (7306)
• Romania
30 Nov 07
It is 2 a.m. right now, when I'm first reading your questions. I promise tomorrow I will answer at least the first one. I really don't feel like doing the math right now.
1 person likes this
@bkpdp1 (920)
• India
6 Dec 07
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@star2453 (129)
• United States
29 Nov 07
Sorry, u asking the wrong guy. (lol) Wanted to say hello anyway, and sorry I can't help you on this
1 person likes this