Netwinner Vs. Moola
By jormins
@jormins (1223)
United States
January 9, 2008 12:25am CST
I've been experimenting with Netwinner for maybe two weeks. Does anyone think Netwinner is better than Moola? I have to say I haven't been real impressed with Netwinner yet. I've tried the $ wheel and Banko and I think my earnings are still near double a day with Moola. Anyone else had a similar experience?
4 responses
@00fear (3216)
• United States
9 Jan 08
i like netwinner better than moola because i like it more than to compete with others. besides that, i have an ecount card of $50 (well $47 -$3 fee) on the way. i like their other prizes too. like restaurant.com and circuit city gift card. yea im also impressed with netwinner and banko. i think the new game, keno49 may be as good as the other two. i have to go back and moola again though. its also cool.
@jormins (1223)
• United States
9 Jan 08
Netwinner charges a $3.00 fee with payout? I hate that because you always find out when you're ready for payout. I'm going to keep playing until I reach payout, then I might cut it loose depending on how much time I have. At least its not a scam though. I hope the new game is something I like. Sometimes the wheel drives me crazy w/ its repetition.
@luvstochat (6907)
• United States
9 Jan 08
I like moola a lot better. I don't get anywhere with netwinner I have never gotten enough points to win anything and its boring just sitting spinning a wheel.
Moola is fun and you earn real cash by playing on there plus they pay by paypal now which is even better!
1 person likes this
@sabbathandruth (567)
• Canada
11 Jan 08
i think with moola you need to upgrade (with money)
i love netwinenr and its free!
@jormins (1223)
• United States
11 Jan 08
I've seen anything about upgrading at Moola. You need an invite to join but its not hard to find an invite.
Befriend me if you need one.
I think I prefer Moola a little more than Netwinner because the games are more exciting. Hi/lo, Rock Scissors Paper Kung Fu.
Netwinner is cool but its basically bingo or the slow $ wheel.