can you solve this?
By Sunil.P
@sunilparthan (6302)
India
6 responses
@abhaijith (2963)
• India
17 Jun 09
hi Sunil,
5Q6?So we have to find the,maximum value of the second digit .right?
here,
5Q6+23Y=800,given
So,
Y+6=10,As the last digit of RHS is zero,
Then,
Y=10-6=4
And,
1+3+Q=10,As the second digit of RHS is zero,
S,
Q=10-4=6.
Q=6,and Y=6
Am i right?
Any way ,i think this discussion is more suitable for the "Problem Solver" interest category.
Good discussion friend.
1 person likes this
@abhaijith (2963)
• India
17 Jun 09
Oh,,ah,,
yeah.
Careless mistake friend.
Yeah,maths is ma fav Subject.
Sure,am interested,Let me see,i will try to solve.
Thanks.
@arkadeb313 (593)
• India
17 Jun 09
hi abhaijith, you did like my kids. solved the problem nicely with proper arguments and while writing the final answer did the blunder. you should have written Y=6 while you showed it as Y=4. deduction of 1 mark ok? dont mind just kidding.
thanks for your nice logic how you solved the problem. it appears that math is a subject of your liking. i just posted a geometry problem, easy one. please help me to solve, if you are interested.
pl carry on
@doctorsubbaiah (412)
• India
17 Jun 09
Hi sunilparthan!
Why don't you start a good 'discussion', this is mathematics.
@boogerman (1544)
• Philippines
17 Jun 09
Hello, sunilparthan! Well, the maximum value for Q is 6. The value of Y should be 4 to have a zero on the ones digit then regroup the tens digit and add 1 to it. The value of Q should be 6 in order to get zero on the tens digit and eight on the hundreds digit so it will get the exact answer of 800. Am I right? 
@whizkid08 (715)
• India
17 Jun 09
What's that "5Q6"??
Well, I can't if it pertains to some higher mathematics.. 
@DoctorDidi (7018)
• India
6 Dec 10
The values of two unknown numbers cannot be determined from one equation. But yet I am calculating it. 0-6=4, so if Y=4, then the equations stands good and the value of Q becomes 6. So Q=6 and Y=4.
