Can you Deny it?????
By saksare
@saksare (10)
Pakistan
August 18, 2010 10:48am CST
well i have a mathematical query in mymind since i started studying algebra 4 years back in school....
can some one help me with this if im wrong or right....
so here is my something called research..(im feeling like newton...=D)
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Suppose we have 2 numbers X & Y..
and X=Y
Multiply both sides with 3
3X=3Y
or
3X-3Y=0
or
3(X-Y)=0
dividing both sides with X-Y
we get
3 = 1
is it possible??????
can 3= 1??
3 responses
@GADHISUNU (2162)
• India
18 Aug 10
x-y is another name for ZERO, as your problem goes. You have been able to draw an absurd conclusion like 1 = 3 or for that matter any number only because you had this "Division by Zero" that is outlawed in Mathematics.
The simple reason is when you divide a finite number by 0 then your quotient could be "anything". Like wise 0/0; 0.inf , inf/inf, inf.inf are all called indeterminate forms, which means there exists no definite answers to these. Hence are to avoided.
If you use them in any form disguised or straight, you end up drawing wrong conclusions. For Logic is the basis of Math or nay rational science. And in Logic from a false hypothesis any conclusion can be drawn. This renders the process of drawing conclusions meanigless
@GADHISUNU (2162)
• India
19 Aug 10
How do you say you haven't divided by 0? for you let X = Y. Therefore X -Y in now not merely an algebraic expression, it is also an alternate name for 0. This like actors in a drama assuming the names of the dramatis personae, but in reality what they are does not get obliterarted. Like wise, 0 is an whole number that is neither positive nor negative, but under the circumstances brought forth by your assumption x - y happens to be an alternate name for 0.
@Warogue678 (165)
• Belarus
18 Aug 10
X-Y 0 right... Then if you want to divide on X-Y you divide on 0. And dividing to 0 is impossible. You get 0=0 You have a mistake. But what you need to find???
@Warogue678 (165)
• Belarus
18 Aug 10
I think it should become like that only if it looks like that
3[(X-Y)/X-Y]= 3
But in your case it's like that
3(X-Y)/(X-Y) =
3x0/(X-Y) =
0/0 =
0
= 0=0
I think it's like that, but I am not sure...
And still I can't understand what's the point of the whole thing.
