Can someone solve this math problem?
By ceasar09
@ceasar09 (442)
Philippines
January 28, 2011 7:24am CST
i am solving this for several hours but i cant figure out how to solve it.
can someone help me.
The problem is under analytic geometry.
Problem:
The slope of the line is 3 times the y intercept and passes through (3,20)
[Ans. 6x-y+2]
3 responses
@uath13 (8192)
• United States
28 Jan 11
Not sure what exactly what your trying to solve for.
If your trying for the slope of 6x-y+2 & goes through 3,20 then you have to find another point along that line. I used 0,8 . the formula for finding slope is (y2-y1)/(x2-x1) so (20-8)/(0-3) , 12/-3 = -4 so the slope of that line is -4.
@RAMPersona (2033)
• Philippines
4 Feb 11
slope of the line,a=(y2-y1)/(x2-x1)
let y1=20 & x1=3
@ y-intercept when x2=0
a=3*y2
so
3*y2=(y2-20)/(0-3)
y2=2
a=6
solving for the equation: y2=y & x2=x
a=(y-y1)/(x-x1)
6=(y-20)/(x-3)
6x-y+2=0
@debate222 (6)
• China
4 Feb 11
My solution:
Suppose the line goes through (0,a). Then according to the question, the slope of the line should be "3a". So we can let the equation of the line be "y=3ax+a". As it goes through (3,20), then we have "3a*3+a=20", which deduce "a=2". So that the equation is y=6x+2, in another word, "6x-y+2=0".
It must be correct, isn't it?
