i have a math prblm::could u do for me please

India
December 26, 2006 11:28am CST
(b+c)(b+c-a)/2bc +(c+a)(c+a-b)/2ca +(a+b)(a+b-c)/2ab = waht?. pleae solve the simple form.i have try too much .but i dont able to do this.please solve the prblm for me.
3 responses
@mythmoh (3984)
• United States
28 Dec 06
i am taking the divisions are only for the numerator and trying to solve it. i will take 1 term b^2+bc-ab+cb+c^2-ac b^2+c^2+2bc-a(b+c)/2bc second term c^2+ac-bc+ac+a^2-ab c^2+a^2+2ac-b(a+c)/2ca third term=a^2+b^2+2ab-c(a+b)/2ab Addind all them taking denaominator as 2abc a(b^2+c^2+2bc-a(b+c))+b(c^2+a^2+2ac-b(a+c))+c(a^2+b^2+2ab-c(a+b))/2abc =ab^2+ac^2+2abc-a^2b-a^2c+bc^2+ba^2+2abc-b^2a-b^2c+ca^2+cb^2+2abc-c^2a-c^2b/2abc =after calcelling out the + and - terms 6abc/2abc =3 Hope i am right.
1 person likes this
• Belgium
30 Dec 06
I think your are rigth...Are you in mathematics?
1 person likes this
• India
8 Jun 07
Thanks dear for a nice try.Yes my dear I am in math.
• India
26 Dec 06
What do u want to do with this maths problem. What do u want me to do. Whether i have to find the values of a, b,c and w, h and t. what do u want us to do? please be clear
• India
27 Dec 06
u have to prove this which i told to do.got it? i give the condotion and now please prove the equation if u could.ok bye.thanx for ur reply.anything more needed then tell me.
• India
27 Dec 06
sorry friend.u should simplified the problem.i want the simple value of this complex form.i can tell the value which would be the answer. this is "3". but i couldnt solve in which i can get the value.please get the value and reply me.
@cnetboss (2473)
• Philippines
29 Dec 06
I got the same answer as with you which is "3"