Yes, I am capable of taking a really bad photograph! Update on the JBL L-100s I am working on.
By The Horse
@TheHorse (218781)
Walnut Creek, California
November 19, 2024 11:14pm CST
I am working on a pair of JBL L-100s right now. They were brought to me by a fellow East Bay musician. These things go for about $1200/pair right now on eBay if they look and sound good.
The ones my friend brought to me are actually in pretty good shape. I think I will be able to make them look minty. But I have to go through my normal ritual. I am sanding down the sides right now. There are scratches, but they are not that deep. The corners look mostly intact.
The surface in the foreground on the top speaker as been sanded down. The lower speaker has not. I took the photo "into the sun" because I had to head out to Guitar Center in the afternoon.
Do you have any slow-moving on-going projects? How was your Tuesday?
6 people like this
6 responses
@LindaOHio (178568)
• United States
21h
You will do a great job. I have all kinds of projects going right now. My Tuesday was good. My husband's 2nd cousin came and worked on my to-do list. Have a good day.
2 people like this
@changjiangzhibin89 (16762)
• China
22h
It is a job requiring fine workmanship ! Wow ! They are worth about $1200/pair !
2 people like this
@TheHorse (218781)
• Walnut Creek, California
18h
In this case, it is mostly just sanding with 150 grit sandpaper, and then oiling them up with orange oil on 0000 steel wool. I have done a bit of work on the corners, but only with wood filler. No "replacement veneer" needed so far.
2 people like this
@Dreamerby (5057)
• Calcutta, India
20 Nov
That's a cool project! Restoring those speakers sounds rewarding. My Tuesday was pretty mundane with college assignments
1 person likes this
@Dreamerby (5057)
• Calcutta, India
17h
@TheHorse Electronics engineering. Currently in 4th year
1 person likes this
@TheHorse (218781)
• Walnut Creek, California
16h
@Dreamerby That sounds interesting. Can you explain to me the difference between impedance and resistance? I remember I = V/R, but some things always befuddled me.
1 person likes this